1810 Delaware gubernatorial election
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| Elections in Delaware |
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The 1810 Delaware gubernatorial election was held on October 2, 1810.
Incumbent Federalist Governor George Truitt was not eligible for re-election under the Delaware Constitution of 1792.
Democratic-Republican nominee Joseph Haslet defeated Federalist nominee Daniel Rodney with 50.49% of the vote.
General election[edit]
Results[edit]
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic-Republican | Joseph Haslet | 3,664 | 50.49% | ||
| Federalist | Daniel Rodney | 3,593 | 49.51% | ||
| Majority | 71 | 0.98% | |||
| Turnout | 7,257 | 100.00% | |||
| Democratic-Republican gain from Federalist | Swing | ||||
References[edit]
- ^ "DE Governor, 1810". Our Campaigns. Retrieved December 8, 2020.
- ^ Congressional Quarterly 1998, p. 46.
- ^ Glashan 1979, pp. 50–51.
- ^ Dubin 2003, p. 26.
Bibliography[edit]
- Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
- Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
- Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.
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