1799 New Jersey gubernatorial election
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The 1799 New Jersey gubernatorial election was held on 29 October 1799 in order to elect the Governor of New Jersey. Incumbent Federalist Governor Richard Howell was re-elected by the New Jersey General Assembly against candidate Andrew Kirkpatrick.[1]
General election
[edit]On election day, 29 October 1799, incumbent Federalist Governor Richard Howell was re-elected by the New Jersey General Assembly by a margin of 18 votes against candidate Andrew Kirkpatrick, thereby retaining Federalist control over the office of Governor. Howell was sworn in for his seventh term that same day.[2][3]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Federalist | Richard Howell (incumbent) | 33 | 68.75% | |
| Andrew Kirkpatrick | 15 | 31.25% | ||
| Total votes | 48 | 100.00% | ||
| Federalist hold | ||||
References
[edit]- ^ "Richard Howell". National Governors Association. Retrieved 30 June 2024.
- ^ "Minutes and proceedings of the Council and General Assembly of the state of New-Jersey, in joint-meeting, from August 30, 1776 to October 29, 1799". archive.org. 14 August 2009. Retrieved 30 June 2024.
- ^ "New Jersey 1799 Governor". elections.lib.tufts.edu. 11 January 2012. Retrieved 30 June 2024.
Categories:
- 1799 New Jersey elections
- 1799 in New Jersey
- New Jersey gubernatorial elections
- 1799 elections
- 1799 elections in North America
- 1799 elections in the United States
- 1790s in New Jersey
- Indirect elections
- 1790s New Jersey elections
- United States gubernatorial elections in the 1790s
- Government of New Jersey
- 1799 United States gubernatorial elections