User contributions for 99.43.139.176
Appearance
Results for 99.43.139.176 talk block log logs global block log filter log
27 May 2011
- 02:1702:17, 27 May 2011 diff hist +781 User talk:Antony-22 →Ocean acidification misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...: new section
- 02:1302:13, 27 May 2011 diff hist +781 User talk:Granitethighs →Ocean acidification misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...: new section
- 02:1202:12, 27 May 2011 diff hist +2 User talk:William M. Connolley →Ocean acidification]] misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...
- 02:1102:11, 27 May 2011 diff hist +779 User talk:William M. Connolley →Ocean acidification]] misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...: new section
- 02:0902:09, 27 May 2011 diff hist −116 User talk:OhanaUnited →Ocean acidification misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...: clean-up
- 02:0902:09, 27 May 2011 diff hist +781 User talk:Will Beback/archive72 →Ocean acidification misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...: new section
- 02:0802:08, 27 May 2011 diff hist +782 User talk:OhanaUnited →Ocean acidification misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...: new section
- 02:0502:05, 27 May 2011 diff hist +4 User talk:Shock Brigade Harvester Boris →Ocean acidification misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...: Organic disamb.
- 02:0402:04, 27 May 2011 diff hist +777 User talk:Shock Brigade Harvester Boris →Ocean acidification misunderstandings with chemistry, carbon, and the usage of organic and inorganic ...: new section
- 01:5501:55, 27 May 2011 diff hist −34 Ocean acidification An "Inorganic chemistry carbon cycle" is impossible. In chemistry to have carbon in the molecule is Organic chemistry. Undid revision 430809161 by Arthur Rubin (talk)